Farnhamville vs Titonka
Side-by-side comparison
How does Farnhamville, IA compare to Titonka, IA? Farnhamville has a population of 417 with a median household income of $55,000, while Titonka has 423 residents and a median income of $54,063. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | Farnhamville, IA | Titonka, IA | Difference |
|---|---|---|---|
| Population | 417 | 423 | -1.4% |
| Median Age | 38.1 | 51.4 | -25.9% |
| Foreign Born % | 0% | 1.4% | -100.0% |
| Metric | Farnhamville | Titonka | Difference |
|---|---|---|---|
| Median Income | $55,000 | $54,063 | +1.7% |
| Unemployment | 0.5% | 2.9% | -82.8% |
| Poverty Rate | 17.2% | 10.4% | +65.4% |
| Bachelor's+ | 10.2% | 16.6% | -38.6% |
| Metric | Farnhamville | Titonka | Difference |
|---|---|---|---|
| Home Value | $69,200 | $61,400 | +12.7% |
| Median Rent | $754/mo | $443/mo | +70.2% |
| Housing Units | 191 | 231 | -17.3% |