Lynnville vs Seymour
Side-by-side comparison
How does Lynnville, IA compare to Seymour, IA? Lynnville has a population of 557 with a median household income of $61,875, while Seymour has 558 residents and a median income of $45,000. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | Lynnville, IA | Seymour, IA | Difference |
|---|---|---|---|
| Population | 557 | 558 | -0.2% |
| Median Age | 43.1 | 51.8 | -16.8% |
| Foreign Born % | 0.5% | 2% | -75.0% |
| Metric | Lynnville | Seymour | Difference |
|---|---|---|---|
| Median Income | $61,875 | $45,000 | +37.5% |
| Unemployment | 2.7% | 0.8% | +190.0% |
| Poverty Rate | 5.7% | 18.4% | -69.0% |
| Bachelor's+ | 18% | 13.4% | +34.3% |
| Metric | Lynnville | Seymour | Difference |
|---|---|---|---|
| Home Value | $139,400 | $78,600 | +77.4% |
| Median Rent | $594/mo | $544/mo | +9.2% |
| Housing Units | 258 | 337 | -23.4% |