Rudd vs Seymour
Side-by-side comparison
How does Rudd, IA compare to Seymour, IA? Rudd has a population of 568 with a median household income of $74,000, while Seymour has 558 residents and a median income of $45,000. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | Rudd, IA | Seymour, IA | Difference |
|---|---|---|---|
| Population | 568 | 558 | +1.8% |
| Median Age | 37.2 | 51.8 | -28.2% |
| Foreign Born % | 3% | 2% | +50.0% |
| Metric | Rudd | Seymour | Difference |
|---|---|---|---|
| Median Income | $74,000 | $45,000 | +64.4% |
| Unemployment | 3.6% | 0.8% | +280.0% |
| Poverty Rate | 12.3% | 18.4% | -33.2% |
| Bachelor's+ | 9.1% | 13.4% | -32.1% |
| Metric | Rudd | Seymour | Difference |
|---|---|---|---|
| Home Value | $104,800 | $78,600 | +33.3% |
| Median Rent | $866/mo | $544/mo | +59.2% |
| Housing Units | 241 | 337 | -28.5% |