Seymour vs Grand Mound
Side-by-side comparison
How does Seymour, IA compare to Grand Mound, IA? Seymour has a population of 558 with a median household income of $45,000, while Grand Mound has 554 residents and a median income of $84,286. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | Seymour, IA | Grand Mound, IA | Difference |
|---|---|---|---|
| Population | 558 | 554 | +0.7% |
| Median Age | 51.8 | 33.7 | +53.7% |
| Foreign Born % | 2% | 0.4% | +160.0% |
| Metric | Seymour | Grand Mound | Difference |
|---|---|---|---|
| Median Income | $45,000 | $84,286 | -46.6% |
| Unemployment | 0.8% | 4.2% | -81.0% |
| Poverty Rate | 18.4% | 12.1% | +52.1% |
| Bachelor's+ | 13.4% | 18.9% | -29.1% |
| Metric | Seymour | Grand Mound | Difference |
|---|---|---|---|
| Home Value | $78,600 | $150,500 | -47.8% |
| Median Rent | $544/mo | $733/mo | -25.8% |
| Housing Units | 337 | 223 | +51.1% |