Seymour vs Lynnville
Side-by-side comparison
How does Seymour, IA compare to Lynnville, IA? Seymour has a population of 558 with a median household income of $45,000, while Lynnville has 557 residents and a median income of $61,875. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | Seymour, IA | Lynnville, IA | Difference |
|---|---|---|---|
| Population | 558 | 557 | +0.2% |
| Median Age | 51.8 | 43.1 | +20.2% |
| Foreign Born % | 2% | 0.5% | +150.0% |
| Metric | Seymour | Lynnville | Difference |
|---|---|---|---|
| Median Income | $45,000 | $61,875 | -27.3% |
| Unemployment | 0.8% | 2.7% | -70.4% |
| Poverty Rate | 18.4% | 5.7% | +222.8% |
| Bachelor's+ | 13.4% | 18% | -25.6% |
| Metric | Seymour | Lynnville | Difference |
|---|---|---|---|
| Home Value | $78,600 | $139,400 | -43.6% |
| Median Rent | $544/mo | $594/mo | -8.4% |
| Housing Units | 337 | 258 | +30.6% |