Seymour vs Rudd
Side-by-side comparison
How does Seymour, IA compare to Rudd, IA? Seymour has a population of 558 with a median household income of $45,000, while Rudd has 568 residents and a median income of $74,000. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | Seymour, IA | Rudd, IA | Difference |
|---|---|---|---|
| Population | 558 | 568 | -1.8% |
| Median Age | 51.8 | 37.2 | +39.2% |
| Foreign Born % | 2% | 3% | -33.3% |
| Metric | Seymour | Rudd | Difference |
|---|---|---|---|
| Median Income | $45,000 | $74,000 | -39.2% |
| Unemployment | 0.8% | 3.6% | -77.8% |
| Poverty Rate | 18.4% | 12.3% | +49.6% |
| Bachelor's+ | 13.4% | 9.1% | +47.3% |
| Metric | Seymour | Rudd | Difference |
|---|---|---|---|
| Home Value | $78,600 | $104,800 | -25.0% |
| Median Rent | $544/mo | $866/mo | -37.2% |
| Housing Units | 337 | 241 | +39.8% |