San Antonito CDP (Bernalillo County), New Mexico vs Santa Fe Foothills
Side-by-side comparison
How does San Antonito CDP (Bernalillo County), New Mexico, NM compare to Santa Fe Foothills, NM? San Antonito CDP (Bernalillo County), New Mexico has a population of 706 with a median household income of $61,250, while Santa Fe Foothills has 710 residents and a median income of $192,630. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | San Antonito CDP (Bernalillo County), New Mexico, NM | Santa Fe Foothills, NM | Difference |
|---|---|---|---|
| Population | 706 | 710 | -0.6% |
| Median Age | 57.2 | 66.7 | -14.2% |
| Foreign Born % | 2.8% | 6.2% | -54.8% |
| Metric | San Antonito CDP (Bernalillo County), New Mexico | Santa Fe Foothills | Difference |
|---|---|---|---|
| Median Income | $61,250 | $192,630 | -68.2% |
| Unemployment | 7% | 0% | +700.0% |
| Poverty Rate | 22.2% | 9.3% | +138.7% |
| Bachelor's+ | 53.5% | 80.1% | -33.2% |
| Metric | San Antonito CDP (Bernalillo County), New Mexico | Santa Fe Foothills | Difference |
|---|---|---|---|
| Home Value | $322,000 | $1,111,500 | -71.0% |
| Median Rent | $0/mo | $0/mo | — |
| Housing Units | 384 | 482 | -20.3% |