San Cristobal vs Arroyo Hondo CDP (Santa Fe County), New Mexico
Side-by-side comparison
How does San Cristobal, NM compare to Arroyo Hondo CDP (Santa Fe County), New Mexico, NM? San Cristobal has a population of 116 with a median household income of $0, while Arroyo Hondo CDP (Santa Fe County), New Mexico has 214 residents and a median income of $125,750. Below you'll find a detailed breakdown of demographics, economy, and housing for both cities.
| Metric | San Cristobal, NM | Arroyo Hondo CDP (Santa Fe County), New Mexico, NM | Difference |
|---|---|---|---|
| Population | 116 | 214 | -45.8% |
| Median Age | 56.2 | 67.4 | -16.6% |
| Foreign Born % | 0% | 2.8% | -100.0% |
| Metric | San Cristobal | Arroyo Hondo CDP (Santa Fe County), New Mexico | Difference |
|---|---|---|---|
| Median Income | $0 | $125,750 | -100.0% |
| Unemployment | 0% | 0% | — |
| Poverty Rate | 0% | 3.7% | -100.0% |
| Bachelor's+ | 21.9% | 70.1% | -68.8% |
| Metric | San Cristobal | Arroyo Hondo CDP (Santa Fe County), New Mexico | Difference |
|---|---|---|---|
| Home Value | $0 | $952,500 | -100.0% |
| Median Rent | $0/mo | $0/mo | — |
| Housing Units | 139 | 138 | +0.7% |